B^2-7b+15=5

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Solution for B^2-7b+15=5 equation:



^2-7B+15=5
We move all terms to the left:
^2-7B+15-(5)=0
determiningTheFunctionDomain -7B+15-5+^2=0
We add all the numbers together, and all the variables
-7B=0
B=0/-7
B=0

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